1.  Syntax

TIMESTAMPDIFF(unit,begin,end); 根據(jù)單位返回時間差,對于傳入的begin和end不需要相同的數(shù)據(jù)結(jié)構(gòu),可以存在一個為Date一個DateTime

2. Unit

支持的單位有

• MICROSECOND
• SECOND
• MINUTE
• HOUR
• DAY
• WEEK
• MONTH
• QUARTER
• YEAR

3. Example

下面這個例子是對于TIMESTAMPDIFF最基本的用法，

• 3.1 求 2017-01-01 - 2017-02-01 之間有幾個月

SELECT TIMESTAMPDIFF(MONTH, '2017-01-01', '2017-02-01') as  result;

+--------+
| result |
+--------+
| 1 |
+--------+
1 row in set (0.00 sec)

• 3.2 求 2017-01-01 - 2017-02-01 之間有幾天

SELECT TIMESTAMPDIFF(DAY, '2017-01-01', '2017-02-01') as  result;

+--------+
| result |
+--------+
| 31 |
+--------+
1 row in set (0.00 sec)

•  3.3 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:00 之間有幾分鐘

SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:00') result;

+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)

•  3.4 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:33 之間有幾分鐘

SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;

+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)

•  3.5 對于DAY， MINUTE進行計算DIFF時，會直接將相對應(yīng)的DAY，MINUTE相減

• 3.6 對于 SECOND 會怎樣計算呢

SELECT TIMESTAMPDIFF(SECOND, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;

55 * 60 + 33 = 3333
+--------+
| result |
+--------+
|   3333 |
+--------+
1 row in set (0.00 sec)

• 3.7 如何求數(shù)據(jù)庫中兩個date字段的diff
  • 3.7.1  建表

    CREATE TABLE demo (id INT AUTO_INCREMENT PRIMARY KEY, start_time DATE NOT NULL, end_time DATE NOT NULL);
    Query OK, 0 rows affected (0.10 sec)

  • 3.7.2  添加數(shù)據(jù)

    INSERT INTO demo(start_time, end_time)
    VALUES('1983-01-01', '1990-01-01'),
    ('1983-01-01', '1989-06-06'),
    ('1983-01-01', '1985-03-02'),
    ('1983-01-01', '1992-05-05'),
    ('1983-01-01 11:12:11', '1995-12-01');

  • 3.7.3 直接query數(shù)據(jù)

    select * from demo;
    +----+------------+------------+
    | id | start_time | end_time |
    +----+------------+------------+
    | 1 | 1983-01-01 | 1990-01-01 |
    | 2 | 1983-01-01 | 1989-06-06 |
    | 3 | 1983-01-01 | 1985-03-02 |
    | 4 | 1983-01-01 | 1992-05-05 |
    | 5 | 1983-01-01 | 1995-12-01 |
    +----+------------+------------+
    5 rows in set (0.00 sec)

  • 3.7.4 計算duration

    select *, TIMESTAMPDIFF(YEAR, start_time, end_time) as duration from demo;
    
    +----+------------+------------+----------+
    | id | start_time | end_time | duration |
    +----+------------+------------+----------+
    | 1 | 1983-01-01 | 1990-01-01 | 7 |
    | 2 | 1983-01-01 | 1989-06-06 | 6 |
    | 3 | 1983-01-01 | 1985-03-02 | 2 |
    | 4 | 1983-01-01 | 1992-05-05 | 9 |
    | 5 | 1983-01-01 | 1995-12-01 | 12 |
    +----+------------+------------+----------+
    5 rows in set (0.00 sec)

  • 3.7.5 其他應(yīng)用

    select *, if(TIMESTAMPDIFF(YEAR, end_time, CURRENT_TIMESTAMP()) 26 ,' 26','>= 26') as result from demo;
    
    +----+------------+------------+--------+
    | id | start_time | end_time | result |
    +----+------------+------------+--------+
    | 1 | 1983-01-01 | 1990-01-01 | >= 26 |
    | 2 | 1983-01-01 | 1989-06-06 | >= 26 |
    | 3 | 1983-01-01 | 1985-03-02 | >= 26 |
    | 4 | 1983-01-01 | 1992-05-05 |  26 |
    | 5 | 1983-01-01 | 1995-12-01 |  26 |
    +----+------------+------------+--------+
    5 rows in set (0.00 sec)

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